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Problem running a function within a function
I am trying to write a function which will take an input and call a function within the function.
x = int(input())
def function1():
function2()
def function2():
print(int(input()) + " on a second line")
function1()
I want the output to be:
2 on a second line
However the program is just returning 2 on a second line. What am I doing wrong here?
A:
The problem is that the function doesn't return anything, so when you do function1(), it executes function2() and returns the value of function2() which is 2.
To correct this, you can rewrite function1() like this:
def function1():
return function2()
Also, note that there is no need for the function2() function as that is what the if __name__ == '__main__': part does. Also, note that you have to call function1() inside the if __name__ == '__main__' else: block to actually run the function.
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